(2x^2+1/x-1)+x=3+(3/x-1)

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Solution for (2x^2+1/x-1)+x=3+(3/x-1) equation: 



(2x^2+1/x-1)+x=3+(3/x-1)

We move all terms to the left:

(2x^2+1/x-1)+x-(3+(3/x-1))=0



Domain of the equation: x-1)!=0

x∈R





Domain of the equation: x-1))!=0

x∈R



We add all the numbers together, and all the variables

x+(2x^2+1/x-1)-(3+(3/x-1))=0

We get rid of parentheses

2x^2+x+1/x-(3+(3/x-1))-1=0

We calculate fractions


2x^2+x+x/x^2+(-(3+(3*x)/x^2-1=0

We add all the numbers together, and all the variables

2x^2+x+x/x^2+(-(3+(+3x)/x^2-1=0

We calculate fractions

We do not support expression: x^4

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